Question

write balanced chemical equation between oxalic acid and sodium hydroxide reaction​

Answer 1

Answer:

H2C2O4(aq) + 2 NaOH(aq) → Na2C2O4(aq) + 2 H2O(i) This equation specifies that there are two moles of H+ supplied by each mole of oxalic acid in this reaction (since 1 mole of H+ is consumed per mole of NaOH).

Answer 2

The balanced chemical equation between oxalic acid and sodium hydroxide reaction​ is $\[{H_2}{C_2}{O_4} + 2NaOH \to N{a_2}{C_2}{O_4} + 2{H_2}O\]$.

Explanation:

• The chemical formula of oxalic acid is $\[{H_2}{C_2}{O_4}\]$ while the chemical formula of sodium hydroxide is $\[NaOH\]$.
• When oxalic acid is treated with sodium hydroxide, it forms sodium oxalate and water.
• The reaction can be written as: $\[{H_2}{C_2}{O_4} + NaOH \to N{a_2}{C_2}{O_4} + {H_2}O\]$
• A balanced chemical reaction is a reaction in which the number of atoms of all the elements of the reactants on the reactant side is equal to the number of atoms of all the elements of the products on the product side.
• To balance sodium and hydrogen atoms on both the sides in the above equation, put 2 as coefficient before $NaOH$ and $\[{H_2}O\]$.
• Therefore, the equation becomes $\[{H_2}{C_2}{O_4} + 2NaOH \to N{a_2}{C_2}{O_4} + 2{H_2}O\]$.

• This is the balanced chemical equation of the reaction between oxalic acid and sodium hydroxide.