WRITE BALANCED CHEMICAL EQUATIONS FOE (A)barium chloride solution reacts with aluminium sulphate solution to form a precipitate of barium sulphate and aluminium chloride solution
Answers
Answered by
9
heya!!
Equation to be balanced -
Barium chloride + Aluminium sulphate → Barium sulphate + Aluminium chloride
Steps -
1. equation is un balanced -
BaCl2 + Al2(SO4)3 → BaSO4 + AlCl3
2. Balancing Aluminium atoms on both sides by multiplying with the coefficient.
BaCl2 + Al2(SO4)3 → BaSO4 + 2AlCl3
3. Balancing Chlorine atoms on both sides by multiplying with the coefficient.
3BaCl2 + Al2(SO4)3 → BaSO4 + 2AlCl3
4. Balancing Barium atoms on both sides by multiplying with suitable coefficient -
3BaCl2 + Al2(SO4)3 → 3BaSO4 + 2AlCl3
5. The balanced eqation formed -
3BaCl2 + Al2(SO4)3 → 3BaSO4 + 2AlCl3
hope it helps!!
Equation to be balanced -
Barium chloride + Aluminium sulphate → Barium sulphate + Aluminium chloride
Steps -
1. equation is un balanced -
BaCl2 + Al2(SO4)3 → BaSO4 + AlCl3
2. Balancing Aluminium atoms on both sides by multiplying with the coefficient.
BaCl2 + Al2(SO4)3 → BaSO4 + 2AlCl3
3. Balancing Chlorine atoms on both sides by multiplying with the coefficient.
3BaCl2 + Al2(SO4)3 → BaSO4 + 2AlCl3
4. Balancing Barium atoms on both sides by multiplying with suitable coefficient -
3BaCl2 + Al2(SO4)3 → 3BaSO4 + 2AlCl3
5. The balanced eqation formed -
3BaCl2 + Al2(SO4)3 → 3BaSO4 + 2AlCl3
hope it helps!!
Answered by
4
3BaCl2 + Al2(S04)3 ---- 3BaS04 + 2AlCl3
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