Question

Write balanced chemical equations for the following statements:
(i) Bleaching powder is kept open in the air.
(ii) blue crystals of copper sulphate are heated.
(iii) chlorine gas is passed through dry slaked lime.
(iv) carbon dioxide gas is passed through lime water.
(v) NaOH solution is heated with zinc granules.

Answer 1

Explanation:

(1)

When Bleaching powder is kept on open air then it reacts with Carbon dioxide and form Calcium Carbonate and Chlorine gas

CaOCl2 + CO2 = CaCO3 + Cl2

(2)

When Blue crystals of Copper Sulphate is heated, then Water molecules removes from CuSO4•5H2O and White Colour of CuSO4 is formed . Blue Colour dissapers when CuSO4•5H2O is heated

CuSO4•5H2O = CuSO4 + 5H2O

(3)

When Chlorine gas is passed through Slaked lime then it form Calcium oxychloride (Bleaching Powder) and Water

Ca(OH)2 + Cl2 = CaOCl2 + H2O

(4)

When Carbon dioxide is pssed through lime Water then it form Calcium Carbonate and water

Ca(OH)2 + CO2 = CaCO3 + H2O

(5)

When Sodium Hydroxide is heated with Zinc Granules then it formed Sodium Zincate and Hydrogen gas

Zn + 2NaOH = Na2ZnO2 + H2