write balanced equation for action of alcoholic KOH on bromoethane
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i) When water is used as solvent, the likeliness of nucleophilic attack by H2O as well as OH- is more. That leads to formation of nucleophilic substituted product.
ii) However in water, the elimination is not favored due to formation of water as one of the product. It is according to le Chatelier’s principle. Excess of water will shift the equilibrium to the left side.
iii) When the reaction is carried out in alcohol, less number of water molecules are available and thus by increasing the chances of attack of OH- ion on β-hydrogen.
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ii) However in water, the elimination is not favored due to formation of water as one of the product. It is according to le Chatelier’s principle. Excess of water will shift the equilibrium to the left side.
iii) When the reaction is carried out in alcohol, less number of water molecules are available and thus by increasing the chances of attack of OH- ion on β-hydrogen.
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maria9:
where is the chemical equation???/
sorry i have forgotten to type it.extremly sorry.
no prob ...... plz correct it :)
okay and thans for forgiving.again sorry
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Hope it helps ^_^.....
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