Question

write briefly about electric intensity at any point due to a charge distribution ....no spam...otherwise will be reported.​

Answer 1

Answer:

hi mate.

Explanation:

Electric Field intensity is the strength of an electric field at any point. It is equal to the electric force per unit charge experienced by a test charge placed at that point , or E = qF .

hope it helps you mate .

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Answer 2

Answer:

electric intensity at any point due to a charge distribution ..it happens when two racidious parts of any metal gets attracted with each other .

thanks..