write cell reaction in lead storage battry during discharge
Answers
Answered by
3
At anode: (oxidation) Pb + SO42–→PbSO4(s) + 2e–
At cathode: (reduction) PbO2(s) + 4H++ SO42–+ 2e– → PbSO4(s) + 2H2O
Net cell reaction: Pb + PbO(s) + 4H+ + 2SO42– → 2PbSO4(s) + 2H2O
At cathode: (reduction) PbO2(s) + 4H++ SO42–+ 2e– → PbSO4(s) + 2H2O
Net cell reaction: Pb + PbO(s) + 4H+ + 2SO42– → 2PbSO4(s) + 2H2O
Similar questions
Social Sciences,
8 months ago
Hindi,
8 months ago
English,
1 year ago
Math,
1 year ago
Social Sciences,
1 year ago
Science,
1 year ago