Write cell reaction of the following electrochemic
cell and calculate e.m.f. and AGº of the cell:
ca|Cd2+||KCI(IM)| HgCl2/s), Hg
[Given : Ecd2
0.40 V and ENCE = 0.28 V]
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Answer:
Eø Cd2+ / Cd = - 0.40 V. The galvanic cell of the given reaction is depicted as: ... + 0.34 V. ΔrGø = -nFEøcell. In the given equation,. n = 6. F = 96487 C mol - 1.
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