Write chemical equation of the reaction of ethanoic acid with the following (i) sodium (ii) ethanol
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1)Ch3cooh +na->ch3coona+h2
2)Ch3cooh +c2h5oh->ch3cooC2h5 +h20
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2)Ch3cooh +c2h5oh->ch3cooC2h5 +h20
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Answered by
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2ch3cooh + 2Na => 2ch3cooNa + H2
ch3cooh + c2h5oh => ch3cooc2h5 + h2o
ch3cooh + c2h5oh => ch3cooc2h5 + h2o
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