write chemical equation of the reaction of ethanoic acid with the following : (i) Sodium (ii) Sodium hydroxide (iii) Ethanol
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(i) The chemical equation when Ethanoic acid reacts with Sodium:
CH3COOH + 2 Na_2CH3COONa + H2
The main product formed is Sodium Ethanoate.
(ii) The chemical equation when ethanoic acid reacts with sodium hydroxide is as follows:
2CH3COOH + NaOH _2 CH3COONa + H2O
The main product formed is Sodium Ethanoate.
(iii) The chemical reaction when ethanoic acid reacts with Ethanol:
2CH3COOH + C2 H5OH _CH3COOC2H5 + H2O
The main product formed is Ethyl Ethanoate.
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CH3COOH + 2 Na_2CH3COONa + H2
The main product formed is Sodium Ethanoate.
(ii) The chemical equation when ethanoic acid reacts with sodium hydroxide is as follows:
2CH3COOH + NaOH _2 CH3COONa + H2O
The main product formed is Sodium Ethanoate.
(iii) The chemical reaction when ethanoic acid reacts with Ethanol:
2CH3COOH + C2 H5OH _CH3COOC2H5 + H2O
The main product formed is Ethyl Ethanoate.
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Answer:
(i) The chemical equation when Ethanoic acid reacts with Sodium:
The main product formed is Sodium Ethanoate.
(ii) The chemical equation when ethanoic acid reacts with sodium hydroxide is as follows:
The main product formed is Sodium Ethanoate.
(iii) The chemical reaction when ethanoic acid reacts with Ethanol:
The main product formed is Ethyl Ethanoate.
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