Question

write chemical equations to show what happens when; (i) ethanol is heated with concentrated sulphuric acid at 443 K.; (ii) ethanol reacts with ethanoic acid in the presence of an acid acting as a catalyst.; (iii) an ester reacts with a base.(All India - 2011)

Answer 1

Answer:

For the reactions refer to the attachment

Answer 2

Chemical equations

(i) Combustion of ethanol in the presence of sulfuric acid

Given:

Reactant - Ethanol ($C_2H_5OH$)

Catalyst - Concentrated Sulfuric acid ($H_2SO_4$)

Temperature - 442 K

Chemical equation:

$C_{2}H_{5}OH\rightarrow CH_2=CH_2$

(ii) Reaction of ethanol and ethanoic acid in the presence of acid acting as a catalyst

Given:

Reactant - Ethanol ($C_2H_5OH$) and ethanoic acid ($CH_3COOH$)

Catalyst - Acid

Chemical equation:

$C_2H_5OH+CH_3COOH\rightarrow CH_3COOC_2H_5+H_2O$

(iii) Reaction of ester with a base

Let the base be sodium hydroxide (NaOH) and ester be ethyl ethonate ($CH_3COOC_2H_5$)

Chemical equation:

$CH_3COOC_2H_5+NaOH\rightarrow CH_3COONa+C_2H_5OH$

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