Question

Write code that counts the number of words in
number
sentence that contain either an "a" or an "e". Store the
result in the variable num a or e.
Note 1 be sure to not double-count words that contain both an a and an e.
HINT 1: Use the in operator.
HINT 2 You can either use or or elif

Answer 1

Python code that counts the number of words in   sentence that contain either an "a" or an "e".

Code:

var=list(str(input("Enter a sentence : ")).split(" "))

count=0

for i in var:

   if ('a' in i) and ('e' in i):

       continue

   if ('a' in i) or ('e' in i):

       count+=1

print(count)

Inputs and outputs:

Input 1:

Enter a sentence : Use any sentence

Output 1:

3

Input 2:

Enter a sentence : Hope you are fine.

Output 2:

2

Explanation:

• Take a sentence as an input and split the words in it by a single space and list them.

• Generate a loop that iterates on each word in the list.

• If the word contains both 'a' and 'e' just continue the loop.

• If the word contains either 'e' or 'a', both not both in it, increment count by one.

• Once all the words are in the list are done with checking, print the count.

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Answer 2

• phyton codes that counts the words in the sentence if they are "A" or "E"

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