Question

Write complete chemical equation in alkaline medium when potassium permanganate oxidizes iodide to iodate

Answer 1

The half equation for the reduction of the permanganate would be

5e−+8H++MnO4− →Mn2++4H2O5eX−+8HX++MnOX4X− →MnX2++4HX2O

But with regards to the iodide, I am very confused. I have seen some sources say that I−IX− is oxidised to IO3−IOX3X− in this reaction, and others saying that it is oxidised to I2IX2.