Question

write conjugate pair of surd ( 3√5 + 5√3 )

Answer 1

The sum and difference of two simple quadratic surds are said to be conjugate surds to each other.

Conjugate surds are also known as complementary surds.

Thus, the sum and the difference of two simple quadratic surds 4√7and √2 are 4√7 + √2 and 4√7 - √2 respectively. Therefore, two surds (4√7 + √2) and (4√7 - √2) are conjugate to each other.

Similarly, two surds (-2√5 + √3) and (-2√5 - √3) are conjugate to each other.

In general, two binomial quadratic surds (x√a + y√b) and (x√a - y√b) are conjugate to each other.

number is multiplied with difference of those two quadratic surds or quadratic surd and rational number, then rational number under root of surd is get squared off and it becomes a rational number as product of sum and difference of two numbers is difference of the square of the two numbers.

a2−b2=(a+b)(a−b).

The sum and difference of two quadratic surds is called as conjugate to each other. For example x−−√ = a and y√ = b, a and b are two quadratic surds, if (a + b) or (x−−√+y√) is multiplied with (a - b) or (x−−√−y√), the result will (x−−√)2 - (y√)2 or (x - y) which is rational number. Here (x−−√+y√) and (x−−√−y√) are conjugate surds to each other and the process is called as rationalization of surds as the result becomes a rational number. This process is used for fraction expression of complex surds, where the denominator needs to converted to a rational number eliminating the roots of surds, conjugate surds multiplied to both numerator and denominator and denominator becomes rational.

Like for example, if simplification of the complex surd 63√−1 is to be done, denominator 3–√−1 is to be converted to a rational number. If a = 3–√ and b = 1, then denominator is (a-b), if we multiply (a + b) or 3–√+1, it will a2−b2 and 3–√ will be squared off.

63√−1

= 6(3√+1)(3√−1)(3√+1)

= 6(3√+1)3−1

= 6(3√+1)2

= 2(\sqrt{3} + 1).

In the above example 3–√+1 is used as rationalizing factor which is a conjugate to 3–√−1.

Note:

1. Since 3 + √5 = √9 + √5 and surd conjugate to √9 + √5 is √9 - √5, hence it is evident that surds 3 + √5 and 3 - √5 are conjugate to each other.

In general, surds (a + x√b) and (a - x√b) are complementary to each other.

2. The product of two binomial quadratic surds is always rational.

For example,

(√m + √n)(√m - √n) = (√m)^2 - (√n)^2 = m - n, which is rational.

Here are some examples of conjugates in the following table.

(2–√+3–√)

(5–√+3–√)

2–√+1

(42–√+23–√)

(x−−√+y)

(ax−−√+by√)

(2–√−3–√)

(5–√−3–√)

2–√−1

(42–√−23–√)

(x−−√−y)

(ax−−√−by√)

Answer 2

Answer:

here is your answer

Step-by-step explanation:

(-_-)sorry I don't Know(^_^)