Write cube of 5 natural numbers which are multiples of 3 and verify the cube of natural number, which is a multiple of 3 is a multiple of 27.
Answers
Answered by
2
Answer:
(3)
3
=3×3×3=27
(6)
3
=6×6×6=216
(9)
3
=9×9×9=729
(12)
3
=12×12×12=1728
(15)
3
=15×15×15=3375
Verification:
(3)
3
=27=27×1
(6)
3
=216=27×8
(9)
3
=729=27×27
(12)
3
=1729=27×64
(15)
3
=3375=27×125
∴ 'The cube of natural number, which is a multiple of 3 is a multiple of 27'.
Answered by
10
Step-by-step explanation:
Let say 5 multiples of 3 = 6, 9, 12, 15, 21
Cube of multiple of 3 are as follows:
- 6³ = 216
- 9³ = 729
- 12³ = 1728
- 15³ = 3375
- 21³ = 9261
Now, we have to verify cube of multiple of 3 is also multiple of 3
So we check above mentioned cubes are multiple of 3 or not.
If those nos. divided by 3 then they are multiple of 3
- 2163 = 72 gives 216 is multiples of 3
- 7293 = 243 gives 729 is multiples of 3
- 1728 + 3 = 576 gives 1728 is multiples of 3
- 33753 = 1125 gives 3375 is multiples of 3
- 92613 = 3087 gives 9261 is multiples of 3
__Hence Verified
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