Write cubes of 5 natural numbers which are multiples of 3 and verify the following
'The cube of a natural number which is a multiple of 3 is a multiple of 27.
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multiples of 3 are 3, 6, 9, 12, 15. cube of 3 is 27 which is a multiple of three. cube of 6 is 216 which is a multiple of 27.Oct 12, 2019
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Answer:
(3)^3=3×3×3=27
(6)^3=6×6×6=216
(9)^3=9×9×9=729
(12)^3=12×12×12=1728
(15)^3=15×15×15=3375
Verification
(3)^3= 27= 27× 1
(6)^3= 216=27×8
(9)^3=729=27×27
(12)^3=1729=27×64
(15)^3=3375=27×125
∴ 'The cube of natural number, which is a multiple of 3 is a multiple of 27'.
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