Question

Write cubes of 5 natural numbers which are multiples of 3 and verify the following . The cube of natural number which is a multiple of 3 is a multiple of 27​

Answer 1

Answer:

${3}^{3 } = 27 = 27 \times 1 = 3 \times 9$

${6}^{3} = 216 = 27 \times 8 = 3 \times 72$

${9}^{3} = 729 = 27 \times 27 = 3 \times 243$

${12}^{3} = 1728 = 27 \times 64 = 3 \times 576$

${15}^{3} = 3375 = 27 \times 125 = 3 \times 1125$

I hope it will help you

Answer 2

Answer:

33=27=27×1=3×9

{6}^{3} = 216 = 27 \times 8 = 3 \times 7263=216=27×8=3×72

{9}^{3} = 729 = 27 \times 27 = 3 \times 24393=729=27×27=3×243

{12}^{3} = 1728 = 27 \times 64 = 3 \times 576123=1728=27×64=3×576

{15}^{3} = 3375 = 27 \times 125 = 3 \times 1125153=3375=27×125=3×1125