Question

Write De Broglie equation. Calculate the mass of a photon with wave length 3.3Ao h=6.626×10−34 J-s​

Answer 1

Answer:

6.693 × 10⁻³³ kg

Explanation:

De Broglie's Equation :

λ = $\frac{h}{mv}$

Where :

λ is the wavelength. (in m)

v is the velocity (in m/s)

m is the mass (in kg)

h is the Planck's constant (in J/Hz or J·s)

Usually h = 6.625 × 10⁻³⁴ J·s

And v = 3 × 10⁸

Given that λ = 3.3 A° and h = 6.626 × 10⁻³⁴ J·s

Procedure :

As λ = $\frac{h}{mv}$

⇒ 3.3 A° = $\frac{6.626 \ * \ 10^{-34}}{(3 \ * \ 10^{8} )m}$

⇒ 3.3 × 10⁻¹⁰ = $\frac{6.626 \ * \ 10^{-34}}{(3 \ * \ 10^{8} )m}$

⇒ 9.9 = $\frac{6.626 \ * \ 10^{-32}}{m}$

⇒ m = $\frac{6.626}{9.9}$ × 10⁻³² kg

⇒ m = 0.6693 × 10⁻³² kg

∴ m = 6.693 × 10⁻³³ kg

Thanks !