Question

write difference between series resonant circuit nd parallel resonanr circuit good ans will be marked as brainlist I want 5points of this question

Answer 1

If we are talking about an RLC circuit, the natural response (resonance) occurs when the inductive reactance is equal to capacitive reactance - though they are 180 degrees out of phase.

For a series network the impedances add as vector quantities, where Z = 0 + jX for an inductor, Z = 0 - jX for a capacitor, and Z = R + j0 for a resistor. Therefore the impedance of the series RLC network is

Z = (R + j0) + (0 + jX) + (0 - jX)

rearranging gives

Z = R(1 + 0 + 0) + j(0 + X -X)

Z = R + j0 = R

For an RLC in a parallel circuit, capacitive reactance and inductive reactance are still equal in magnitude and opposite in phase, but the overall impedance is highly dependent on the placement of the resistor.

In series circuit with R, L, and C components, the XL = XC, and total impedance is just the resistance part.

VL - VC + VR = V source

It is to be noted that individually VC and VL , Voltages across capacitor and inductor can be much higher than supply voltage , can even reach very dangerous levels if resistance is low , and total current is V/R. In the absence of resistance, the circuit behaves like a short circuit to the voltage source.

In parallel resonance, with these three components in parallel to each other, each component draws its own current. Again XL = XC, and lagging reactive current of ideal inductor is fully nullified by leading capacitor reactive current. In the absence of R, net current drawn from voltage source (supply) is zero. The system is thus open circuit. If R is present, the only current drawn is that taken by R.

Answer 2

here is ur answer

hope u get it

if you have any doubt then ask me the comment section

thank you for asking the question