Question

Write differentiation (dy/dx)

When y = sin x


y = cosx

y = tanx

y = sec x

y = cot x

Answer 1

Hey.....!!☺

Here's ur ans. ⬇

↪ y = sinx

dy / dx = cos x


.


.↪ y = cos x

dy / dx = -sinx



.

↪ y = tanx

dy/dx = sec^2 x




.
↪ y = sec x

dy/dx = sec x tan x


.

↪ y = cot x

dy/dx = -cosec^2 x




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✌Hope it helps

Answer 2

y = sin x

Therefore, dy/dx = cos x.

y = cosx

Therefore , dy/dx = - sin x.

y = tanx

Therefore, dy/dx = sec square 2 x.

y = sec x

Therefore, dy/dx = sec square x tan x.

y = cot x

Therefore, dy/dx = -codec square 2 x.