write differentiation of the following 1)x/cosx
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Answer:
Let y=xxcosx+x2−1x2+1
Also, let u=xxcosx and v=x2−1x2+1
∴y=u+v
⇒dxdy=dxdu+dxdv ...(1)
u=xxcosx
⇒logu=log(xxcosx)
⇒logu=xcosxlogx
Differentiating both sides with respect to x, we obtain
u1dxdu=dxd(x).cosx.logx+xdxd(cosx).logx+xcosx.dxd(logx)
⇒dxdu=u[1.cosx.
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