Question

write differentiation of the following 1)x/cosx​

Answer 1

Answer:

Let y=xxcosx+x2−1x2+1

Also, let u=xxcosx and v=x2−1x2+1

∴y=u+v

⇒dxdy=dxdu+dxdv             ...(1)

u=xxcosx

⇒logu=log(xxcosx)

⇒logu=xcosxlogx

Differentiating both sides with respect to x, we obtain

u1dxdu=dxd(x).cosx.logx+xdxd(cosx).logx+xcosx.dxd(logx)

⇒dxdu=u[1.cosx.