Question

write discrinants of the quadratic equation √3x²-2√2(x+1)-2=0​

Answer 1

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here is your answer

Answer:

X= -√2/3 or -√6

Step-by-step explanation:

√3x^2 - 2√2x -2√3 = 0 (given)

√3x^2 -3√2x + √2x -2√3 = 0

[3√2× √2 = 6 & -3√2+ √2 = -2√2]

√3x (x-√6 ) + √2 ( x-√6) = 0

(√3x + √2 ) ( x -√6 ) = 0

√3x + √2 = 0 or x - √6 = 0

√3x = -√2 or x = √6

x = -√2/√3 or x = √6

x = - √2/3 or x = √6

hence, the roots of the quadratic equation√3x^2 - 2√2x - 2√3 = 0 are

-√(2/3) & -√6

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Answer 2

Step-by-step explanation:

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