Math, asked by 29sharmaaasha, 5 months ago

write divisibility rule of 2,3,4,5,6,7,8,9,10,11​

Answers

Answered by thegamingzone555
1

Divisibility Test for 2: The last digit is 0, 2, 4, 6, or 8.

Divisibility Test for 3: The sum of the digits is divisible by 3.

Divisibility Test for 5: The last digit is 0 or 5.

Divisibility Test for 7: Cross off last digit, double it and subtract. Repeat if you want. If new number is divisible by 7, the original number is divisible by 7.

Divisibility Test for 11: For a 3-digit number, sum of the outside digits minus the middle digit must be 0 or 11

The basic rule for divisibility by 4 is that if the number formed by the last two digits in a number is divisible by 4, the original number is divisible by 4; this is because 100 is divisible by 4 and so adding hundreds, thousands, etc. is simply adding another number that is divisible by 4.

Answered by Rushaan123
0

Answer:

Divisibility Tests for 2, 3, 5, 7 and 11

This shows you the divisibility tests for 2, 3, 5, 7, and 11, so you can tell if those numbers are factors of a given number or not without dividing.

Divisibility Test for 2: The last digit is 0, 2, 4, 6, or 8.

Divisibility Test for 3: The sum of the digits is divisible by 3.

Divisibility Test for 5: The last digit is 0 or 5.

Divisibility Test for 7: Cross off the last digit, double it and subtract. Repeat if you want. If the new number is divisible by 7, the original number is divisible by 7.

Divisibility Test for 11: For a 3-digit number, the sum of the outside digits minus the middle digit must be 0 or 11.

Divisibility Tests for 11 and 13: Goes over two divisibility tests for 11 and also the one for 13.

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