write divisibility rule of 2,3,5,7,9,11 with one example of each
Answers
Step-by-step explanation:
The divisibility rule of 2 is that the last digit is even number then that given would be divisible by 2.
The divisibility rule of 3 is that the sum of all digit of that given number would be divisible by 3.
The divisibility rule of 5 is that the last digit of that given number is 0 or 5 then that number would be divisible by 5.
The divisibility rule of 7 is that the last digit of the given number is doubled and thereafter subtract that result from the rest of the number,if that resulting number is divisible by 7.
The divisibility rule of 9 is same as the method of 3.
The divisibility rule of 11 is that we have to take the alternating sum of the digits in the number,read from left to right.If that is divisible by 11,sothat is the number which would be divisible by 11.
Answer:
(1.)Divisibility of 2 :- A no. divisible by 2 only when its unit digit is 0,2,4,6 0r 8.
(2)Divisibility of 3 :- A no. divisible by 3 only when the sum of digit is divisible by 3.
(3)Divisibility of 5 :- A no. divisible by 5 only when its unit digit is 0 or 5.
(4)Divisibility of 7 :- A no. divisible by 7 if (the no. excluding the unit digit) - (2 × digit) is a no. divisible by 7. Example = 672 = 67-(2×2) = 67-4=63
(5)Divisibility of 9 :- Same as divisibility of 3.
(6)Divisibility of 11 :- A no. divisible by 11 if the difference between the sum of its digit at odd places and the sum of its digit at even place is either 0 or a no. divisible by 11.
Example = 863478 = Odd place = 8+4+6 = 18
Even place = 7+3+8 = 18 = Difference = 18-18=0 which is divisible by 11.