Question

write divisibility test rule of 2,3,4,5,6,8,910 and 11 step by step explained​

Answer 1

Answer:

2 the last digit should be 2,4,6,8,0

3 the sum of all the digits should be the multiple of 3

5 the last digit should be 5, 0

6 the no. should be divided by both 2and 3

10 the last digit should be 0 only

11- for eg- 5678 is divisible by 11 or not then we have to add like this 8+6= 14

5+8 = 13

then subtract 14-13 = 1 the result should be 0, 11, or multiple of 11 if the result is any of the no. of the no. as I have written above then, the no.is divisible by 11 otherwise the no. is not divisible

as 5678 is not divisible by 11

Answer 2

${ \boxed{ \boxed{ \bold \red{Divisibility \: test \: rule \: of \: 2}}}}$

If a number ends in a 0, 2, 4, 6 or 8, it is divisible by 2. All even numbers, by definition, are divisible by 2.

${ \boxed{ \boxed{ \bold \red{Divisibility \: test \: rule \: of \: 3}}}}$

If the sum of the digits of a number is divisible by 3, then the number is divisible by 3. Some examples of numbers divisible by 3 are as follows. The number 85203 is divisible by 3 because the sum of its digits 8+5+2+0+3=18 is divisible by 3.

${ \boxed{ \boxed{ \bold \red{Divisibility \: test \: rule \: of \: 4}}}}$

The basic rule for divisibility by 4 is that if the number formed by the last two digits in a number is divisible by 4, the original number is divisible by 4; this is because 100 is divisible by 4 and so adding hundreds, thousands, etc. is simply adding another number that is divisible by 4.

${ \boxed{ \boxed{ \bold \red{Divisibility \: test \: rule \: of \: 5}}}}$

Divisibility by 5 is easily determined by checking the last digit in the number (475), and seeing if it is either 0 or 5. If the last number is either 0 or 5, the entire number is divisible by 5. If the last digit in the number is 0, then the result will be the remaining digits multiplied by 2.

${ \boxed{ \boxed{ \bold \red{Divisibility \: test \: rule \: of \: 6}}}}$

That is, if the last digit of the given number is even and the sum of its digits is a multiple of 3, then the given number is also a multiple of 6. Example: 630, the number is divisible by 2 as the last digit is 0. The sum of digits is 6+3+0 = 9, which is also divisible by 3.

${ \boxed{ \boxed{ \bold \red{Divisibility \: test \: rule \: of \: 8}}}}$

If the last three digits of a number are divisible by 8, then the number is completely divisible by 8. Consider the last two digits i.e. 344. As 344 is divisible by 8, the original number 24344 is also divisible by 8.

${ \boxed{ \boxed{ \bold \red{Divisibility \: test \: rule \: of \: 9}}}}$

If the sum of the digits of a number is divisible by 9, then the number is divisible by 9. Some examples of numbers divisible by 9 are as follows. The number 51984 is divisible by 9 because the sum of its digits 5+1+9+8+4=27 is divisible by 9.

${ \boxed{ \boxed{ \bold \red{Divisibility \: test \: rule \: of \: 10}}}}$

Divisibility rule for 10 states that any number whose last digit is 0, is divisible by 10. Example: 10, 20, 30, 1000, 5000, 60000, etc.

${ \boxed{ \boxed{ \bold \red{Divisibility \: test \: rule \: of \: 11}}}}$

If the number of digits is even, add the first and subtract the last digit from the rest. The result must be divisible by 11. If the number of digits is odd, subtract the first and last digit from the rest. The result must be divisible by 11.