write divisibilty rules of 2,3,4,6,9 and 11 with examples.
Answers
Answer:
Divisibility Rules for Numbers 2, 3, 4, 5, 6, 9 and 10
A number is divisible by 2 if the last digit of the number is 0, 2, 4, 6, or 8.
Solution: Since the last digit of the number 246 ends in 6, that means it is divisible by 2.
Answer:
This shows you the divisibility tests for 2, 3, 5, 7, and 11, so you can tell if those numbers are factors of a given number or not without dividing.
Divisibility Test for 2: The last digit is 0, 2, 4, 6, or 8.
Divisibility Test for 3: The sum of the digits is divisible by 3.
Divisibility Test for 5: The last digit is 0 or 5.
Divisibility Test for 7: Cross off last digit, double it and subtract. Repeat if you want. If new number is divisible by 7, the original number is divisible by 7.
Divisibility Test for 11: For a 3-digit number, sum of the outside digits minus the middle digit must be 0 or 11.