Write domain and range of the relation R defined on A={0,1,2,3,4,5} by R = {(x,x+3),x€A}
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Answer:
domain ={0,1,2}
Range = {3,4,5}
Step-by-step explanation:
given that f(d) = x
f(R) = x+3 let it's equal to y
as both functions belong to A
so,
if x = 0 , y = 3 belongs to A
similarly for x = 1,2 y belongs to A. but
for x = 3 , y = 6 which does not belongs to A.
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