Question

write double bond equivalent of the following compound?​

Answer 1

Answer:

DBE =  7

Explanation:

DBE = x+1 - (y/2)

where x= no. of carbon atoms

y = no. of hydrogen atoms

divalent atoms are ignored

For the present example the formula is C23H34O2

Therefore

DBE = (23+1) - (34/2) = 7

The present structure contains 2 double bond and 5 cycles.