Question

Write down a relation between electric flux and electric field
intensity??​

Answer 1

Explanation:

Electric flux is given by EACosx.

where x is angle between area vector and electric field

And electric field is KQ/r^2

on put value of electric field in flux equation

Flux=kQACosx/r^2 (rî).

(rî) for vectorial representation

Hope it helps you....

Answer 2

$\huge \boxed{answer} \\ \\ \\ \sf {\boxed {\boxed{\phi \: = \: ES \: cos \theta}}} \\ \\ \phi \: = electric \: flux \\ E \: = \: electric \: field \: intensity \\ S \: = \: surface \: area$

$\mathscr{\large{Thanks}}\heartsuit$