Question

write down all trigonometry formulas

Answer 1

I think these are enough.
If more u can ask,
Above are some of the formula.
If u want I will answer identities also

Answer 2

$TRIGONOMETRY$
$FORMULAE$
★★★★★★★★★★★★



Trigonometry is used to analyze the relationship between angles heights and lengths of triangles. The fundamentals of trigonometry are introduced in class 10 and have been summarized below.
In a right-angled triangle, the Pythagoras theorem states

(perpendicular )2 + ( base )2 = ( hypotenuse )2

There are some properties pertaining to the right-angled triangle. It is to be noted that in the following formulas, P stands for perpendicular, B stands for base and H stands for the hypotenuse.

•SinA = P / H

•CosA = B / H

•TanA = P / B

•CotA = B / P

•CosecA = H / P

•SecA = H/B

•Sin2A + Cos2A = 1

•Tan2A + 1 = Sec2A

•Cot2A + 1 = Cosec2A

In order to find a relationship between various trigonometric identities, there are some important formulas:

1. TanA = SinA / CosA
2. CotA = CosA / SinA
3. CosecA = 1 / SinA
4. SecA = 1 / CosA

There are some formulas that are very crucial to solving higher level sums.

•Sin (A +B) =SinA . CosB + CosA . SinB

•Sin (A – B) = SinA . CosB – CosA . SinB

•Cos (A + B) = CosA . CosB – SinA . SinB

•Cos (A – B) = CosA. CosB + SinA . SinB

•Tan (A + B) = TanA + TanB / 1 – TanA . TanB

•Tan (A – B) = TanA –TanB / 1 + TanA . TanB

•Sin ( A + B) . Sin (A – B) = Sin2A – Sin2B = Cos2B – Cos2A

•Cos (A + B) . Cos (A – B) = Cos2A – Sin2B = Cos2B – Sin2A

•Sin2A = 2 . SinA . CosA = 2 . TanA / (1 + Tan2A)

•Cos2A = Cos2A – Sin2A = 1 – 2Sin2A = 2Cos2A – 1 = (1 – Tan2A) / (1 + Tan2A)

•Tan2A = 2TanA / (1 – Tan2A)

•Sin3A = 3 . SinA – 4 . Sin3A

•Cos3A = 4 . Cos3A – 3 . CosA

•Tan3A = (3TanA – Tan3A) / (1 – 3Tan2A)

•SinA + SinB = 2 Sin (A + B)/2 Cos (A – B)/2

•SinA – SinB = 2 Sin (A – B)/2 Cos (A + B)/2

•CosA + CosB = 2 Cos(A – B)/2 Cos (A + B)/2

•CosA – CosB = 2 Sin(B – A)/2 Sin (A + B)/2

•TanA + TanB = Sin (A + B) / CosA . CosB

•SinA CosB = Sin (A + B) + Sin (A – B)

•CosA SinB = Sin (A + B) – Sin (A – B)

•CosA CosB = Cos (A + B) + Cos (A – B)

•SinA SinB = Cos (A – B) – Cos (A + B)




♥️♥️MAY THIS HELP U MY FRND!!!!