Question

Write down an ionic equation for the reaction at the negative electrode during electrolysis of aqueous  CuSO4.​

Answer 1

Answer:

Copper is less reactive than hydrogen, so copper (Cu) is produced at the negative electrode. The half equation is: Cu2+ + 2e- → Cu The hydroxide ion is more reactive than the sulphate ion, therefore this forms water (H2O) and oxygen at the positive electrode.

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Answer 2

Answer:

Copper is less reactive than hydrogen, so copper (Cu) is produced at the negative electrode. The half equation is: Cu2+ + 2e- → Cu The hydroxide ion is more reactive than the sulphate ion, therefore this forms water (H2O) and oxygen at the positive electrode.