write down Assignment the Condition - I for which the following pair linea equation have no Solution, hence find the value of k.
2x-3y = 6 3x - (K-2)y=9
Answers
Answer:
please mark me brain list
Step-by-step explanation:
Given pair of linear equations:
2x+3y=9 ---(1)
6x+(k-2)y=3k-2 ----(2)
Compare these equations with
a1x+b1y=c1 and a2x+b2y=c2
we get
\begin{gathered} a_{1}=2, b_{1}=3\\a_{2}=6,b_{2}=k-2 \end{gathered}
a
1
=2,b
1
=3
a
2
=6,b
2
=k−2
Now ,
\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}
a
2
a
1
=
b
2
b
1
/* Given linear equations have no solution */
\implies \frac{2}{6}=\frac{3}{k-2}⟹
6
2
=
k−2
3
Do the cross multiplication, we get,
\implies 2(k-2)=6\times 3⟹2(k−2)=6×3
\implies k-2 = \frac{6\times3}{2}⟹k−2=
2
6×3
\implies k-2=9⟹k−2=9
\implies k = 9+2⟹k=9+2
\implies k = 11⟹k=11
Therefore,
k = 11
••••
Step-by-step explanation:
Answer
2x+3y=9,6x+(k−2)y=(3k−2)
These given equations are in the form:
a
1
x+b
1
y+c
1
=0 and
a
2
x+b
2
y+c
2
=0
Where
a
1
=2,b
1
=3 and c
1
=9
a
2
=6,b
2
=(k−2) and c
2
=(3k−2)
a
2
a
1
=
6
2
,
b
2
b
1
=
k−2
3
,
c
2
c
1
=
3k−2
9
a
2
a
1
=
b
2
b
1
=
c
2
c
1
Therefore, the system has no solution.
Now,
2/6=3/(k−2)
2k−4=18
or k=11
Since
b
2
b
1
=
c
2
c
1
3/9
=9/31
Which is true. The value of k is 11.