Question

Write down equation for elimination reaction and mention major product of 2 chlorobutane.​

Answer 1

Answer:

Rate = k[RX][Base]

Answer 2

Elimination reaction of 2 chlorobutane

Explanation:

• Firstly define the elimination reaction, it is the type that involves chemical reaction in which two substituent group is removed from the given molecule.
• Alkyl halide can eliminate HX and forms alkene.
• Major alkene will be the one which is stable i.e. hyperconjuction stabilise.
• In case of 2 chlorobutane, 2-Butene is the major alkene formed and 1-Butene is minor one.
• The elimination reaction is shown as-

      $CH_3-CH(Cl)-CH_2-CH_3 \overset{alc. KOH}{\rightarrow} CH_3-CH=CH-CH_3 + CH_2=CH-CH_2-CH_3$