Question

Write down number of zeroes and find also. 6x² - 3x + 2x - 1.​

Answer 1

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Answer 2

$p(x) = 6{x}^{2} - 3x + 2x - 1 = 0\\3x(2x - 1) + 1(2x - 1) = 0 \\ (3x + 1)(2x - 1) = 0 \\ 3x + 1 = 0 \: or \: 2x - 1 = 0 \\ x = \frac{ - 1}{3} \: or \: x = \frac{1}{2}$