write down solubility equation. At 25degree Celsius temperature. how much gram of water needed to prepare saturated solution with 240 gram of pottasuim chloride.(solubility of pottasuim chloride at 25 degree Celsius is 48)
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weight of salt = 90 gram,
solubility = 50
sing formula
solubility of solute =
weightofsolventinsaturatedsolution
weightofsoluteinsaturatedsolution
×100
or 50=
weightofsolventinsaturatedsolutiiion
90gm
×100
so weight of solvent in saturated solution =
50
90gm
×100=180gm
Hence 180 gm of water is required to prepare a saturated solution.
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