Question

Write down the anode and cathode reaction in Copper-Silver battery? How many electron process is this?
please answer it properly

Answer 1

Answer:

hello

Explanation:

The half-reaction on the anode, where oxidation occurs, is Zn(s) = Zn2+ (aq) + (2e-). The zinc loses two electrons to form Zn2+. The half-reaction on the cathode where reduction occurs is Cu2+ (aq) + 2e- = Cu(s). Here, the copper ions gain electrons and become solid copper.

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Answer 2

Explanation:

Answer:

hello

Explanation:

The half-reaction on the anode, where oxidation occurs, is Zn(s) = Zn2+ (aq) + (2e-). The zinc loses two electrons to form Zn2+. The half-reaction on the cathode where reduction occurs is Cu2+ (aq) + 2e- = Cu(s). Here, the copper ions gain electrons and become solid copper.

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