Question

Write down the anode and cathode reaction in Copper-Silver battery?
How many electron process is this?
plz answer it correctly
and plz who dont know what it is plz dont write i dont know sorry
dont even try to do it i will report you

Answer 1

The half-reaction on the anode, where oxidation occurs, is Zn(s) = Zn2+ (aq) + (2e-). The zinc loses two electrons to form Zn2+. The half-reaction on the cathode where reduction occurs is Cu2+ (aq) + 2e- = Cu(s). Here, the copper ions gain electrons and become solid copper.

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