Write down the atomic number and mass number each of the element produced when and 92U238 radiates one Alpha particle and then successively two beta particles ?Please tell..
Answers
Answer:
When an alpha particle is emitted from a radioactive substance its atomic number(Z) decreases by 2 and mass number(A) decreases by 4. When β particle is emitted from a radioactive substance its atomic number(Z) increases by 1 and mass number(A) does not change.
Here, Uranium decays to lead its mass no changes to by 24 i.e.
24/4 =6α particles are emitted and hence, its atomic
number changes by 12 but the atomic numbre of Pis 10 this is due to emission of two β particle.
238/92 U→6α4/2+2β0/1 + 214/82Pb.
Explanation:
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Answer:
When an alpha particle is emitted from a radioactive substance its atomic number(Z) decreases by 2 and mass number(A) decreases by 4. When β particle is emitted from a radioactive substance its atomic number(Z) increases by 1 and mass number(A) does not change.
Here, Uranium decays to lead its mass no changes to by 24 i.e.
424=6α particles are emitted and hence, its atomic
number changes by 12 but the atomic numbre of Pb is 10 this is due to emission of two β particle.
92238U→6α24+2β10+82214Pb
Explanation:
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