Math, asked by palakchhipa2000, 4 months ago

Write down the decimal expansion of 1/200

Answers

Answered by ranganathranganath36
3

representation in base-10 (i.e., in the decimal system). In this system, each "decimal place" consists of a digit 0-9 arranged such that each digit is multiplied by a power of 10, decreasing from left to right, and with a decimal place indicating the 10^0=1s place. For example, the number with decimal expansion 1234.56 is defined as

1234.56 = 1×10^3+2×10^2+3×10^1+4×10^0+5×10^(-1)+6×10^(-2)

(1)

= 1×1000+2×100+3×10+4+5×1/(10)+6×1/(100).

(2)

Expressions written in this form sum_(k)b_k10^k (where negative k are allowed as exemplified above but usually not considered in elementary education contexts) are said to be in expanded notation.

Other examples include the decimal expansion of 25^2 given by 625, of pi given by 3.14159..., and of 1/9 given by 0.1111.... The decimal expansion of a number can be found in the Wolfram Language using the command RealDigits[n], or equivalently, RealDigits[n, 10].

The decimal expansion of a number may terminate (in which case the number is called a regular number or finite decimal, e.g., 1/2=0.5), eventually become periodic (in which case the number is called a repeating decimal, e.g., 1/3=0.3^_), or continue infinitely without repeating (in which case the number is called irrational).

The following table summarizes the decimal expansions of the first few unit fractions. As usual, the repeating portion of a decimal expansion is conventionally denoted with a vinculum.

fraction decimal expansion fraction decimal expansion

1 1 1/(11) 0.09^_

1/2 0.5 1/(12) 0.083^_

1/3 0.3^_ 1/(13) 0.076923^_

1/4 0.25 1/(14) 0.0714285^_

1/5 0.2 1/(15) 0.06^_

1/6 0.16^_ 1/(16) 0.0625

1/7 0.142857^_ 1/(17) 0.0588235294117647^_

1/8 0.125 1/(18) 0.05^_

1/9 0.1^_ 1/(19) 0.052631578947368421^_

1/(10) 0.1 1/(20) 0.05

If r=p/q has a finite decimal expansion (i.e., r is a regular number), then

r = (a_1)/(10)+(a_2)/(10^2)+...+(a_n)/(10^n)

(3)

= (a_110^(n-1)+a_210^(n-2)+...+a_n)/(10^n)

(4)

= (a_110^(n-1)+a_210^(n-2)+...+a_n)/(2^n·5^n).

(5)

Factoring possible common multiples gives

r=p/(2^alpha5^beta),

(6)

where p≢0 (mod 2, 5). Therefore, the numbers with finite decimal expansions are fractions of this form. The first few regular numbers are 1, 2, 4, 5, 8, 10, 16, 20, 25, 32, 40, 50, ... (OEIS A003592).

Any nonregular fraction m/n is periodic, and has a decimal period lambda(n) independent of m, which is at most n-1 digits long. If n is relatively prime to 10, then the period lambda(n) of m/n is a divisor of phi(n) and has at most phi(n) digits, where phi is the totient function. It turns out that lambda(n) is the multiplicative order of 10 (mod n) (Glaisher 1878, Lehmer 1941). The number of digits in the repeating portion of the decimal of a rational number can also be found directly from the multiplicative order of its denominator.

When a rational number m/n with (m,n)=1 is expanded, the period begins after s terms and has length t, where s and t are the smallest numbers satisfying

10^s=10^(s+t) (mod n).

(7)

When n≢0 (mod 2, 5), s=0, and this becomes a purely periodic decimal with

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