write down the electronic configuration according to Bohr's model of the given elements :oxygen and aluminium
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Oxygen=atomic no(8)
Aluminum=atomic no(13)
so according to Bohr's model, there is 2 element in 1st orbit, 8 in 2nd orbit and8 in other orbit
so K=2e
L=8e and
M, N=8 e
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ELECTRONIC CONFIGURATION OF OXYGEN = 2
ELECTRONIC CONFIGURATION OF ALUMINIUM = 3
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