Chemistry, asked by itzmanu48, 8 months ago

Write down the electronic configuration of:

(i) Cr3+ (ii) Pm3+ (iii) Cu+ (iv) Ce4+ (v) Co2+ (vi) Lu2+ (vii) Mn2+  (viii) Th4+

Answers

Answered by Anonymous
8

Explanation:

1. Cr3+ = 1s2 2s2 2p6, 3s2 3p6 3d3

2. Cu+ = 1s2, 2s2, 2p6, 3s2, 3p6, 3d10

3. Co2+ = 1s2, 2s2, 2p6, 3s2, 3p6, 3d7

4. Mn2+ = 1s2, 2s2, 2p6, 3s2, 3p6, 3d5

5. Pm3+ = 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2, 4d10, 5p6 4f4

6. Ce4+ = 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2, 4d10, 5p6

7. Lu2+ = 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2, 4d10, 5p6 4f14, 5d1

8. Th4+ = 1s2, 2s2, 2p6, 3s2, 3p6, 3d10, 4s2, 4p6, 4d10, 4f14, 5s2, 5p6, 5d10, 6s2, 6p6

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Answered by ThakurRajSingh24
10

 \dag \:   \: \red{ \rm{ \underline{Explanation :- }}}

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(i) Cr3+: 1s² 2s² 2p^6 3s² 3p^6 3d³

Or, [Ar]18 3d³

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(ii) Pm3+: 1s² 2s² 2p^6 3s² 3p^6 3d^10 4s² 4p^6 4d^10 5s² 5p^6 4f^4

Or, [Xe]54 3d³

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(iii) Cu+: 1s² 2s² 2p^6 3s² 3p^6 3d^10

Or, [Ar]18 3d^10

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(iv) Ce4+: 1s² 2s² 2p^6 3s² 3p^6 3d^10 4s² 4p^6 4d^10 5s² 5p^6

Or, [Xe]54

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(v) Co2+: 1s² 2s² 2p^6 3s² 3p^6 3d^7

Or, [Ar]18 3d^7

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(vi) Lu2+: 1s² 2s² 2p^6 3s² 3p^6 3d^10 4s² 4p^6 4d^10 5s² 5p^6 4f^14 5d¹

Or, [Xe]54 2f^14 3d³

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(vii) Mn2+: 1s²2s² 2p^6 3s² 3p^6 3d^5

Or, [Ar]18 3d^5

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(viii) Th4+: 1s² 2s²2p^6 3s² 3p^6 3d^10 4s²4p^6 4d^10 4f^14 5s² 5p^6 5d^10 6s² 6s^6

Or, [Rn]862+

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