Chemistry, asked by tidkeaditya6, 10 months ago

Write down the electronic configuration of 's and Ti.​

Answers

Answered by 8298525725kk
1

Answer:

electronif configuration of Sulphur is (Ne)3s2,3p4

and of Xe 4f14,5d,10,6s2,6p1

Answered by qwmagpies
0

The electronic configuration of Sulfur is

 {1s}^{2}  {2s}^{2}  {2p}^{6}  {3s}^{2}  {3p}^{4}

The electronic configuration of Ti is

{1s}^{2}  {2s}^{2}  {2p}^{6}  {3s}^{2}  {3p}^{6}  {4s}^{2}  {3d}^{2}

  • Sulfur is a group of 16 elements. It is an element of the oxygen family. It has the atomic number 16 and the mass number 32. The electronic configuration of Sulfur is-
  • {1s}^{2}  {2s}^{2}  {2p}^{6}  {3s}^{2}  {3p}^{4}
  • Ti has the atomic number 22. It is a transition element. It is also called a 3d block element. In Ti, the valance electrons reside at 3d subshell. The electronic configuration of Ti is-
  • {1s}^{2}  {2s}^{2}  {2p}^{6}  {3s}^{2}  {3p}^{6}  {4s}^{2}  {3d}^{2}

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