Write down the equation for electrolysis of water.
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Answered by
2
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H
2
SO
4
(l)+2H
2
O(l)→2H
3
O
+
(aq)+SO
4
2−
(aq)
At cathode,
2H
3
O
+
(aq)+2e
−
→H
2
(g)+2H
2
O(l) (reduction)
At anode:
2H
2
O(l)→O
2
(g)+4H
+
(aq)+4e
−
(oxidation)
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Answer:
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Explanation:
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