Question

write down the first four terms of the sequences whose general terms are tn =3 n+1​

Answer 1

Answer:

i use simple trick so learn it

tn = 3n+1

put n=1

t(1)= 3×1 +1 = 4

n=2

t(2)= 3×2 +1 =7

n=3

t(3) = 3×3 +1 =10

so you can see that it make an A.P with common difference 3

series is 4,7,10.......

plz mark as brainliet.....................

Answer 2

Given,

The general term of a sequence: tn = 3n + 1

To find,

The first four terms of the sequence.

Solution,

We can simply solve this mathematical problem using the following process:

According to the question;

The general term of a sequence: tn = 3n + 1

Now,

The first term of the sequence

The first term of the sequence= t1= 3(1) + 1 = 4

The second term of the sequence

The second term of the sequence= t2 = 3(2) + 1 = 7

The third term of the sequence

The third term of the sequence= t3 = 3(3) + 1 = 10

The fourth term of the sequence

The fourth term of the sequence= t4 = 3(4) + 1 = 13

Hence, the first four terms of the sequence are 4, 7, 10, and 13, respectively.