Physics, asked by vishalsritej19, 1 day ago

write down the formulae for the refractive index of a liquid determined by in a newtons ring experiment​

Answers

Answered by xeronytekoustuv
0

Answer:

In Newton's ring experiment, the space between the plano-convex lens and the flat glass is filled with a liquid of refractive index n1=1.80 and the radius of the 20th dark ring is measured to be X1. Then this liquid is replaced with another one having a refractive index n2. In this case, radius of the same order dark ring is measured as X2=1.20*X1.

a) Calculate n2.

b) If the radius of the 20th dark ring is 3mm when the first liquid (n1=1.80) is used, calculate the radius of curvature of the plano-convex lens. Assume a monochromatic light of λ=0.54μm

c) Speculate what would the interference pattern look like, if the liquid had a gradient refractive index varying as n=A+Bt where A and B are constant and t is the thickness of the liquid at the given point.

Explanation:

Answered by aliasgarabidi
0

Answer:

3 is anwer yes this is anser

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