Question

write down the law of moment
​

Answer 1

Answer:

total initial momentum = total final momentum..

Explanation:

Answer is in short and easy word..

follow me mate..

Answer 2

$\large{\underline{\underline{\red{\tt{\purple{\leadsto } LaW\:Of\:MomenT:-}}}}}$

When a number of parallel forces act on a rigid body and the body is in equilibrium , then the algebraic sum of the the moments of the individual forces about any point is equal to zero . That is the sum of anticlockwise moments is equal to the sum of clockwise moments.

It is also known as Varignon's theorem.

_________________________________

$\large{\underline{\underline{\red{\tt{\purple{\leadsto } ExperimenT\:To\:FinD\:WeighT\:Of\:BodY:-}}}}}$

$\tt [ For \: figure\: refer \:to \:attachment:]$

$\tt\green{Step\:\:1\::}$Metre scale is supported at its centre by a knife edge so that the scale is horizontal.

$\tt\green{Step\:\:2\::}$ the unknown weight $\sf(W_1)$is suspended on one side of the scale as shown and unknown weight $\sf(W_2)$ is suspended on the other side.

$\tt\green{Step\:\:3\::}$ The two weights are adjusted and position on the scale until the scale remains horizontal (equilibrium position).

$\tt\green{Step\:\:4\::}$ Distance $\sf(d_1)$between unknown weight and the centre of the scale is noted down similarly distance $(d_2)$between the known weight at the centre of scale is also noted down .

$\tt\green{Step\:\:5\::}$ From the principle of moments,

$\tt:\implies W_1 \times d_1 = W_2\times d_2$

$\blue{\underbrace{\orange{\underline{\underline{\boxed{\red{\tt{\longmapsto \:\:W_1\:\:=\:\:\dfrac{W_2\times d_2}{d_1}}}}}}}}}$

$\bf\blue {Hence\: unknown\: weight\:can\:be\:determined. }$