Write down the main point of valance shair electron pair reduction
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1.Six valence electrons on the central S atom.
Three F atoms contribute one electron each.
2.One electron from the N σ-bond.
Donate two electrons from S to the two π-bonds.
3.Eight electrons left around central S, ≡ four valence shell electron pairs.
4.Hence a tetrahedral geometry.
5. The bond-bond repulsions however are not all equal. The SN bond repels the three SF bonds more than the S-F bonds repel each-other.
6.Hence the N-S-F angle is greater than the F-S-F angle, a distorted tetrahedron.
Three F atoms contribute one electron each.
2.One electron from the N σ-bond.
Donate two electrons from S to the two π-bonds.
3.Eight electrons left around central S, ≡ four valence shell electron pairs.
4.Hence a tetrahedral geometry.
5. The bond-bond repulsions however are not all equal. The SN bond repels the three SF bonds more than the S-F bonds repel each-other.
6.Hence the N-S-F angle is greater than the F-S-F angle, a distorted tetrahedron.
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