Write down the mechanism of alkaline hydrolysis of tert butyl bromide
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This SN1 reaction takes place in three steps:
Formation of a tert-butyl carbocation by separation of a leaving group (a bromide anion) from the carbon atom: this step is slow and reversible.[4]
Recombination of carbocation with nucleophile
Nucleophilic attack: the carbocation reacts with the nucleophile. If the nucleophile is a neutral molecule (i.e. a solvent) a third step is required to complete the reaction. When the solvent is water, the intermediate is an oxonium ion. This reaction step
Formation of a tert-butyl carbocation by separation of a leaving group (a bromide anion) from the carbon atom: this step is slow and reversible.[4]
Recombination of carbocation with nucleophile
Nucleophilic attack: the carbocation reacts with the nucleophile. If the nucleophile is a neutral molecule (i.e. a solvent) a third step is required to complete the reaction. When the solvent is water, the intermediate is an oxonium ion. This reaction step
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Explanation:
Answer is:-
The hydrolysis of methyl bromide involves SN2 mechanism, as there is an attack of a nucleophile and so the nucleophile attacks from back side as the former side is captured by the -ve bromide ion. This reaction is single step reaction and involves substitution where the molecularity of reaction is 2 as it involves two molecules.
At first, the KOH releases the -OH -group which attacks on the +vely charged C-atom of methyl bromide from back side.
I Hope you are satisfied with this answer.
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