Question

write down the no of electron lost or gain in the following reaction 2cr 3+—cr​

Answer 1

Explanation:

We will then take multiples of each reaction until the number of electrons on each ... We can write these electrons explicitly as products: ... 2 × [Cr → Cr 3+ + 3e −] = 2 Cr → 2 Cr 3+ + 6e −

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Answer 2

2cr 3+—cr

Cr → 2 Cr3+ + 6e−...

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