Question

Write down the number of ligands of metals in following.
[ Fe( CN ) 6 ] ^-4. & [ Ni (CO)4]

Answer 1

Answer:

In both cases no of metals -1

No of ligands in First complex=6

No of ligands in second case-=4

Answer 2

The number of ligands in [Fe(CN)₆]⁴⁻ and [Ni(CO)₄] are 6 and 4 respectively.

• The ligands are ions or molecules which are attached to the central metal ion directly through a coordinate bond. The ligand attached to the central metal can be negatively charged, positively charged as well as neutral.
• Examples of positively charged ligands are NO⁺(Nitrosonium) and NO₂⁺(Nitronium). There are negatively charged ligands like Cl⁻(Chlorido) and CN⁻(Cyano) and there exist neutral ligands also such as H₂O(Aqua), NH₃(Ammine), and CO(Carbonyl).
• The magnitude of the oxidation state of the central metal ion is known as 'Primary Valency'. Whereas the number of ligands attached to the central metal is known as 'Secondary Valency'. The secondary valency of a coordination compound can be calculated by counting the number of ligands lying inside the coordination sphere.
• Thus by counting the number of ligands lying inside the coordination sphere of [Fe(CN)₆]⁴⁻ and [Ni(CO)₄] we can the secondary valency of these molecules.

Hence the number of ligands in [Fe(CN)₆]⁴⁻ and [Ni(CO)₄] are 6 and 4 respectively.

#SPJ2