Question

write down the Pythagoras theorem and prove that in triangle PQR angle =90° then PR2=PQ2 + Qr2​

Answer 1

Answer:

Step-by-step explanation:

This is converse of Pythagoras theorem

We can prove this contradiction sum q2 =p  2  +r  2

 in ΔPQR while triangle is not a rightangle

Now consider another triangle ΔABC we construct ΔABC AB=qCB=b and C is a Right angle

By the Pythagorean theorem

(AC) 2 =p  2  +r  2

But we know p  2+r  2  =q  2  and q=PR  

So (AB)  2  =p  2 +r  2  =(SR)  2

 

Since PQ and AB are length of sides we can take positive square roots

AC=PQ

All the these sides ΔABC are congruent to ΔPQR  

So they are congruent by sss theorem

Answer 2

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